2011 澳洲 AMC C-Junior 真题 答案 详解
2011-10-10序号 | 文件列表 | 说明 | ||
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1 | 2011-C-Junior-paper-eng-zh.pdf | 6 页 | 396.25KB | 中英双语真题 |
2 | 2011-C-Junior-paper-eng.pdf | 6 页 | 193.96KB | 英文真题 |
3 | 2011-C-Junior-key.pdf | 1 页 | 12.00KB | 真题答案 |
中英双语真题
Primary Exam Paper (Grades 7-8)
1-10 questions, 3 points each
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Calculate (2011 - 1102): (A) 1111 (B) 1191 (C) 1001 (D) 989 (E) 909
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In the right triangle, find the value of (x): (A) 75 (B) 80 (C) 85 (D) 90 (E) 95
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I went for a walk at 2:15 PM and returned home at 3:20 PM. How long did I spend walking? (A) 50 minutes (B) 55 minutes (C) 60 minutes (D) 65 minutes (E) 70 minutes
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On the number line, what is the coordinate of the point that is 15 units to the left of point Q? (A) -10 (B) -9 (C) 0 (D) 5 (E) 10
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Simplify (888 - (88 - 8)): (A) 808 (B) 880 (C) 800 (D) 792 (E) 2011
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Given (5 \times 7 \times 11 = 385), calculate (0.5 \times 0.7 \times 0.11): (A) 38.5 (B) 3.85 (C) 0.385 (D) 0.0385 (E) 0.00385
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Lines PT, QU, RV, and SW all intersect at point O. Given (\angle QOR = 20^\circ), (\angle SOT = 50^\circ), and (\angle VOW = 70^\circ). Find the measure of (\angle POQ): (A) 30° (B) 40° (C) 50° (D) 60° (E) 80°
英文真题
Junior Division
Questions 1 to 10, 3 marks each
-
The value of (2011 - 1102) is
(A) 1111
(B) 1191
(C) 1001
(D) 989
(E) 909 -
In the diagram, the value of (x) is
(A) 75
(B) 80
(C) 85
(D) 90
(E) 95 -
I left for a walk at 2:15 pm and returned at 3:20 pm. How long was I out walking?
(A) 50 minutes
(B) 55 minutes
(C) 60 minutes
(D) 65 minutes
(E) 70 minutes -
On this number line,
the point 15 units to the left of (Q) is
(A) -10
(B) -9
(C) 0
(D) 5
(E) 10 -
The value of (888 - (88 - 8)) is
(A) 808
(B) 880
(C) 800
(D) 792
(E) 2011 -
We know that (5 \times 7 \times 11 = 385). What is the value of (0.5 \times 0.7 \times 0.11)? (A) 38.5
(B) 3.85
(C) 0.385
(D) 0.0385
(E) 0.00385