2012 澳洲 AMC A-MiddlePrimary 真题 答案 详解

中英双语真题

Primary School Middle Grades (3-4th Grade) Test Paper 1-10 questions, 3 points each

1. Calculate 48 - 25 equals: (A) 63 (B) 17 (C) 27 (D) 13 (E) 23

2. What is the area of this rectangle in square meters? (A) 9 (B) 10 (C) 12 (D) 14 (E) 16

3. Arrange the following cards in order to form the largest five-digit number: Card P: 11 Card Q: 7 Card R: 10 (A) PQR (B) QRP (C) QPR (D) PRQ (E) RQP

4. Add one-tenth, one-hundredth, and two-thousandths together. What is their sum? (A) 112 (B) 1.12 (C) 300 (D) 0.112 (E) 0.13

5. Xiaowu's football team won against their opponents by two goals, and a total of 8 goals were scored during the match. How many goals did Xiaowu's team score in total? (A) 3 (B) 4 (C) 5 (D) 6 (E) 8

英文真题

Middle Primary Division
Questions 1 to 10, 3 marks each

1. The value of (48 - 25) is
   (A) 63 (B) 17 (C) 27 (D) 13 (E) 23

2. The area, in square metres, of the rectangle below is
   (A) 9 (B) 10 (C) 12 (D) 14 (E) 16

3. In which order would you place the following cards to make the largest 5-digit number?
   Card P: 11
   Card Q: 7
   Card R: 10
   (A) PQR (B) QRP (C) QPR (D) PRQ (E) RQP

4. What should we get if we add one tenth, one hundredth and two thousandths?
   (A) 112 (B) 1.12 (C) 300 (D) 0.112 (E) 0.13

5. Mary's soccer team wins a game by two goals. Between them the two teams scored 8 goals. How many goals did Mary's team score?
   (A) 3 (B) 4 (C) 5 (D) 6 (E) 8

真题文字详解(英文)

Middle Primary Division - Solutions
1. The value of 48 - 25 is 23, hence (E).
2. The area is the length times the width, so is 2 × 7 = 14 square metres, hence (D).
3. Clearly, the largest 5-digit number will have the largest digit in the first position, and so the first digit must be the 7. The next largest digit is 1, and the next is 1, so the number is 71 110 and the order of the cards is QPR, hence (C).
4. Adding one tenth, one hundredth and two thousandths gives 0.112, hence (D).
5. (Also UP2) We look for two numbers, 2 apart which add to 8. These are 5 and 3, so Mary's team scored 5 goals, hence (C).
6. (Also UP3) The chance of a rabbit with spinner A is (\frac{3}{8}); with spinner B is (\frac{2}{4});