2013 澳洲 AMC C-Junior 真题 答案 详解
2013-10-08序号 | 文件列表 | 说明 | ||
---|---|---|---|---|
1 | 2013-C-Junior-paper-eng-zh.pdf | 7 页 | 270.27KB | 中英双语真题 |
2 | 2013-C-Junior-paper-eng.pdf | 8 页 | 74.93KB | 英文真题 |
3 | 2013-C-Junior-key.pdf | 1 页 | 11.17KB | 真题答案 |
4 | 2013-C-Junior-solution-eng.pdf | 11 页 | 356.68KB | 真题文字详解(英文) |
中英双语真题
Primary Paper
Questions 1-10, 3 points each
- The expression (1999 + 24) equals:
- (A) 1923
- (B) 2003
- (C) 2013
- (D) 2023
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(E) 2113
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In the diagram, (PQR) is a straight line. Find the value of (x):
- (A) 40
- (B) 90
- (C) 100
- (D) 110
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(E) 120
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Which fraction (\frac{1}{2}) is closest to?
- (A) 0.45
- (B) 0.6
- (C) (\frac{1}{3})
- (D) (\frac{5}{8})
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(E) (\frac{2}{5})
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Which expression equals 20?
- (A) (3 + 2 \times 4)
- (B) ((9 + 5) \times 2 - 4 \times 2)
- (C) (10^2)
- (D) (20 + 20 \div 2)
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(E) (10 \div 2)
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How many minutes are there from 8:37 am to 10:16 am?
- (A) 39
- (B) 79
- (C) 99
- (D) 141
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(E) 179
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Three squares with an area of (25 \text{ cm}^2) are joined side by side to form a rectangle. What is the perimeter of this rectangle?
- (A) 20
- (B) 36
- (C) 40
- (D) 75
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(E) 100
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If a positive integer has digits that can only be 3 or 5, which property always holds true for such numbers?
- (A) Divisible by 3
- (B) Divisible by 5
- (C) Prime number
- (D) Even number
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(E) Odd number
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A point (P) lies at position 0.56 on a scale, while point (Q) is at position 1.2. Where is the midpoint between (P) and (Q)?
- (A) 0.34
- (B) 0.64
- (C) 0.83
- (D) 0.88
- (E) 0.93
英文真题
Junior Division
Questions 1 to 10, 3 marks each
-
1999 + 24 is equal to
(A) 1923 (B) 2003 (C) 2013 (D) 2023 (E) 2113 -
PQR is a straight line. Find the value of x.
(A) 40 (B) 90 (C) 100 (D) 110 (E) 120 -
The value of the fraction ( \frac{1}{2} ) is closest to
(A) 0.45 (B) 0.6 (C) ( \frac{1}{3} ) (D) ( \frac{5}{8} ) (E) ( \frac{2}{5} ) -
Which of the following is equal to 20?
(A) 3 + 2 × 4 (B) (9 + 5) × 2 − 4 × 2 (C) 10² (D) 20 + 20 ÷ 2 (E) 10 ÷ 2 -
How many minutes are there between 8:37 am and 10:16 am?
(A) 39 (B) 79 (C) 99 (D) 141 (E) 179 -
Three squares each with an area of 25 cm² are placed side by side to form a rectangle. The perimeter, in centimetres, of the rectangle is
(A) 20 (B) 36 (C) 40 (D) 75 (E) 100 -
If every digit of a whole number is either a 3 or a 5, the number will always be
(A) divisible by 3 (B) divisible by 5 (C) prime (D) even (E) odd -
P is the point at 0.56 and Q is the point at 1.2 on a number line. The point which is halfway between P and Q is at
(A) 0.34 (B) 0.64 (C) 0.83 (D) 0.88 (E) 0.93
真题文字详解(英文)
SOLUTIONS - JUNIOR DIVISION 1. 1999 + 24 = 2023, hence (D). 2. As the angle on a straight line is 180°, x° = 180° − (10° + 20° + 30°) = 180° − 60° = 120°, hence (E). 3. We know that ( \frac{1}{2} = 0.5 ), so absolute differences are (A) 0.05, (B) 0.1, (C) ( \frac{1}{6} > 0.16 ), (D) ( \frac{1}{8} = 0.125 ) and (E) 0.1. The smallest of these differences is 0.05. Thus, the fraction ( \frac{1}{2} ) is closest to 0.45, hence (A). 4. (A) 3 + 2 × 4 = 11 (B) (9 + 5) × 2 − 4 × 2 = 20 (C) 10² = 100 (D) 20 + 20 ÷ 2 = 30 (E) 10 ÷ 2 = 5 hence (B). 5. From 8:37 am to 9 am is 23 minutes, from 9 am to 10 am is 60 minutes and from 10 am to 10:16 am is 16 minutes: 23 + 60 + 16 = 99 minutes, hence (C). 6. A square with an area of 25 cm² is 5 cm × 5 cm so the rectangle formed from three of these squares will have sides of 5 cm and 15 cm, giving a perimeter of 40 cm, hence (C). 7. (Also I3) If every digit of a whole number is either a 3 or a 5, the number must be odd. Note that 33 is not prime, even or divisible by 5 and 35 is not divisible by 3, showing that odd is the only consistent descriptor, hence (E). 8. The point halfway between P and Q is the average of the two numbers. (0.56 + 1.2) ÷ 2 = 0.88 hence (D).